3x^2-96x+768=0

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Solution for 3x^2-96x+768=0 equation: 



3x^2-96x+768=0

a = 3; b = -96; c = +768;
Δ = b2-4ac
Δ = -962-4·3·768
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{96}{6}=16$

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